Q1.) If x = a n * 3 2 * (3 -n/2 ) -2 -(27) n = 1 3 3m * 2 3 27 Show that m = 1+ b Q2.) If x = √( 3 + 2√ 2) √ (5 – 2√6) Show that x 2 (x-6) 2 = 1

Question

Q1.) If x = a n * 3 2 * (3 -n/2 ) -2 -(27) n = 1 3 3m * 2 3 27 Show that m = 1+ b Q2.) If x = &radic;( 3 + 2&radic; 2) &radic; (5 &ndash; 2&radic;6) Show that x 2 (x-6) 2 = 1

Aman Bansal · Answer

Dear Devansh,

I think there is some error in your first question,

In order to solve second one , simplify x to lowest term and hen substitute in given equation.

Best Of luck

Plz Approve the answer...!!!!

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Q1.) If x = a n * 3 2 * (3 -n/2 ) -2 -(27) n = 1 3 3m * 2 3 27 Show that m = 1+ b Q2.) If x = √( 3 + 2√ 2) √ (5 – 2√6) Show that x 2 (x-6) 2 = 1

Q1.)         If x = aⁿ * 3² * (3^-n/2)^-2 -(27)ⁿ = 1

                             3^3m * 2³ 27

                   Show that m = 1+ b

Q2.)       If   x = √(3 + 2√ 2)

                          √ (5 – 2√6)

                    Show that x² (x-6)² = 1

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Q1.) If x = a n * 3 2 * (3 -n/2 ) -2 -(27) n = 1 3 3m * 2 3 27 Show that m = 1+ b Q2.) If x = √( 3 + 2√ 2) √ (5 – 2√6) Show that x 2 (x-6) 2 = 1

Q1.) If x = an * 32 * (3-n/2)-2 -(27)n = 1 33m * 23 27 Show that m = 1+ b Q2.) If x = √(3 + 2√ 2) √ (5 – 2√6) Show that x2 (x-6)2 = 1

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Q1.) If x = aⁿ * 3² * (3^-n/2)^-2 -(27)ⁿ = 1

3^3m * 2³ 27

Show that m = 1+ b

Q2.) If x = √(3 + 2√ 2)

√ (5 – 2√6)

Show that x² (x-6)² = 1