Then number of all possible matrices of order 3 X 3 with each entry 0 and 1 is :(A) 27(B) 18(C) 81(D) 51The correct answer is (D)But I don't understand the question and the answer as well!!Can anyone please explain me this question and how to get and answer? :)

Dear Chanchal,

there are nine entries possible...

every entry has two choices ..either 0 or 1,...

so no, of ways we can make up such a matrix..is 2*2*2...nine times...or simply ..2^9...

Best Of luck

Plz Approve the answer...!!!!

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Then number of all possible matrices of order 3 X 3 with each entry 0 and 1 is :