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An A.P. has even number of terms, the first term of which is unity.S1 & S2 stand for the sum of its first n terms & last n terms such that S1/S2 = q. What is the common difference of the A.P.?
let d be common difference. S1=(n/2)(2+(n-1)d) S2=(n/2)((1+nd)+(n-1)d), ((2n-1)d+1)/((n-1)d+2)=(1/q)
(2n-1)d+1=((n-1)/q)d+(2/q), d=((2/q)-1)/((2n-1)-((n-1)/q))
thannkyou chetan, but it is a question from M.L. khanna, problem set 92 of progressions (Q.25 c part) and in the solutions, the ans. is given as 2. along with this a hint is also given which reads : S1/S2 = Sn/S2n - Sn = q.put n = 1,2. actually i m not getting this..would u please help...i really want to make into IITb & i m preparing myself for jee. so your explaination will be of great help to me.
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