Chetan Mandayam Nayakar
Last Activity: 13 Years ago
(x-a)(x-b)/(x-c) =k(real), x2-(a+b)x+ab=kx-kc, x2-(a+b+k)x+ab+kc=0,if x is real, discriminant≥0,(a+b+k)^2≥4(ab+kc)
k2+(a+b)2+2k(a+b)≥4(ab+kc), k2+2k(a+b-2c)+(a-b)^2≥0,k≤-(a+b-2c)-√((a+b-2c)2-(a-b)2)
or k≥-(a+b-2c)+√((a+b-2c)2-(a-b)2)