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sir, how to solve -- 2^log18tobase6 * 3^log3tobase6
Since log 6 18= log 6 6*3=log 6 6 + log 6 3=1+log 6 3 ,
the question reduces to 21+log63*3log63= 2*6log63 = 2*3 = 6
QUESTION:
2^log18tobase6 * 3^log3tobase6
ANSWER:
As log 6 18= log 6 6*3=log 6 6 + log 6 3=1+log 6 3
Therefore, 21+log63*3log63= 2*6log63 = 2*3 = 6
( BASICALLY IT REQUIRES PROPERTIES OF LOGARITMS)
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