sir, how to solve -- 2^log18tobase6 * 3^log3tobase6

Since log ₆ 18= log ₆ 6*3=log ₆ 6 + log ₆ 3=1+log ₆ 3 ,

 the question reduces to 2^1+log₆3*3^log₆3= 2*6^log₆3 = 2*3 = 6

QUESTION:

ANSWER:

As  log ₆ 18= log ₆ 6*3=log ₆ 6 + log ₆ 3=1+log ₆ 3 

Therefore, 2^1+log₆3*3^log₆3= 2*6^log₆3 = 2*3 = 6

( BASICALLY IT REQUIRES PROPERTIES OF LOGARITMS)