Algebra
if !z!=3, the area of triangle whose sides are z, wz and z+wz (where w is a complex cube root of unity) is
if !z!=3, the area of triangle whose sides are z, wz and z+wz (where w is a complex cube root of unity) is
1 Answer
Jitender Singh
Ans:
Hello Student,
Please find answer to your question below
|z| = 3
The sides of the triangle are |z|, |wz|, |z+wz|.
|z| = 3
|wz| = |w||z| = 3
|z + wz| = |z(1+w)| = |z||1+w| = 3
So they form an equilateral triangle.
Area:
Hello Student,
Please find answer to your question below
|z| = 3
The sides of the triangle are |z|, |wz|, |z+wz|.
|z| = 3
|wz| = |w||z| = 3
|z + wz| = |z(1+w)| = |z||1+w| = 3
So they form an equilateral triangle.
Area:
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