cos(1-i) = a+ib (a,b are reals), then which is correct
a) a=1\2(e - 1\e)cos1, b=1\2(e+ 1\e)sin1
b) a=1\2(e + 1\e)cos1, b=1\2(e - 1\e)sin1
c) a=1\2(e + 1\e)cos1, b=1\2(e+ 1\e)sin1
d) a=1\2(e - 1\e)cos1, b=1\2(e-1\e)sin1
cos(1-i) = a+ib (a,b are reals), then which is correct
a) a=1\2(e - 1\e)cos1, b=1\2(e+ 1\e)sin1
b) a=1\2(e + 1\e)cos1, b=1\2(e - 1\e)sin1
c) a=1\2(e + 1\e)cos1, b=1\2(e+ 1\e)sin1
d) a=1\2(e - 1\e)cos1, b=1\2(e-1\e)sin1