Probablity and statistics

Question

A die is tossed twice. A is the event 'the sumof the two numbers uppermost is greater than 5', B the event 'the sum of the two numbers uppermost is less than 8'. Find the probability of these events:(a) A(b) B(c) AB(d) A U BHence show that P(A U B)=P(A)+P(B)-P(A ^ B).Are A and B mutually exclusive?

Jitender Singh · Accepted Answer

Ans:Hello Student,Please find answer to your question belowLet x & y be the random number occuring on die 1st & 2nd time respectively.Then for the 1steventx + y > 5Number of possiblity(1,5), (1,6), (2,4), (2,5), (2,6), (3,3), (3,4), (3,5), (3,6), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3),(5,4),(5,5), (5,6),(6,1), (6,2), (6,3),(6,4), (6,5), (6,6)Total possibility = 36For the 2ndevent:x + y > 8(3,6), (4,5), (4,6), (5,4),(5,5), (5,6), (6,3),(6,4), (6,5), (6,6)No they are not mutually exclusive. As you can see there is an intersection b/w events of A & B.

Algebra> Probablity and statistics...

A die is tossed twice. A is the event 'the sumof the two numbers uppermost is greater than 5', B the event 'the sum of the two numbers uppermost is less than 8'. Find the probability of these events:(a) A(b) B(c) AB(d) A U BHence show that P(A U B)=P(A)+P(B)-P(A ^ B).Are A and B mutually exclusive?

Burhan Tayyab , 13 Years ago

Jitender Singh

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Algebra> Probablity and statistics...

A die is tossed twice. A is the event 'the sumof the two numbers uppermost is greater than 5', B the event 'the sum of the two numbers uppermost is less than 8'. Find the probability of these events:(a) A(b) B(c) AB(d) A U BHence show that P(A U B)=P(A)+P(B)-P(A ^ B).Are A and B mutually exclusive?

Burhan Tayyab , 13 Years ago

Jitender Singh

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

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