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If α and β are the roots of the equation, 2x2 –3x –6 =0, then equation whose roots are α2+2, β2 +2 is< how to solve
friend its we have formula
x2 –x{a+b}+ab where a and b are roots of eq then find a and b from the eq and substitute in a sruare +2 and b square +2 and apply above formula (a=alpha b=beta} pls approve
usin sum of roots and product of roots required eqn will be of form x2+(α2+β2+4)x + (α2+2)*(β2+2)=0
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