Grade 12Algebra
If A + B + C = 180° then the value of tanA + tanB + tanC is : how to solve
If A + B + C = 180° then the value of tanA + tanB + tanC is : how to solve
1 Answer
Sudheesh Singanamalla
we have A+B=180-C
tan(A+B)=tan(180-C)
[tanA+tanB]/[1-tanAtanB] = -tanC
tanA + tanB = - tanC+ tanA * tanB * tanC
tanA + tanB + tanC = tanA * tanB * tanC
Please approve
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