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Number of real roots of the equation esin x –e-sin x -4 = 0 is
esin x.esin x-4esin x-1=0
esin x=(4+2 )/2 , (4-2 )/2
=2+ ,2-
approve if u like....
ans: zero
on solvin tha quadratic in e^(sinx) we obtain values 2+√5 and 2-√5 => sinx = ln(2+√5)/ln(2-√5)
ln(2+√5) > 1 and ln(2-√5)- is nt defined
hence der is no real root for given equation.....
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