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What are the number of digits in 1! + 2! + 3!.......+100! ?
no. of digits in 1!=1
no.of digits in 2!=2..........
no. of digits in 100!=100.
So what we need to find is the sum of series-1,2,3,4.......100
we can use the formula n(n+1)/2
=>100*101/2
=>5050
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