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if the equation [b-c]x2+[c-a]x+a-c=0,,,,has equal roots then prove 2b=a+c
Dear aditya,
I think there is some problem in question. As you have told equation has equal roots then its descriminant will be 0
so B2=4AC
[c-a]2=4[b-c][a-c] on solving this you get 4b=3c+a
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