find the coefficient of 1/y2 in (y+c3/y2)10

Dear kaif ali,

we know that,         T_r=nC_r(I)^n-r(II)^r

=>T₄=10C₄(y)^10-4(c³/y²)⁴

=>T₄=210(y)⁶(c¹²/y⁸)

=>T₄=210(c¹²/y²)

so, coefficient of  i/y2  is  210c¹²

I hope you understand 

(y+c3/y2)10  = (10y+10c3)/y2

=1/y2*(10y+10c3)

coeff. of 1/y2 is (10y+10c3)

approve if u  like

w.k.t  

T_r+1=¹⁰Cr.y^10-r[(c3)/y2]^r

      therefore by simplifyin we get

y^2r-10+r=y²

therefore 2r-10+r=2

so r=4

simplify in eqn 1

v get t5=¹⁰c₄.y².c¹²

so coeff of y2 =210*c¹²

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!