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what are number of ways of selcting 3 squares on a normal chess board so that theydont belong to same row column and diagonal line?explain
64C3-1148.Calculate the ways in which 3 boxes can be selected which are in a straight line.This can be divided into 2:1) Diagonal=2*(3C3+4C3+5C3+....8C3)=2522) Vertical/Horizontal=2*(8*8c3)=896Subtract this from the total number of ways of selecting 3 boxes on the chess board. This gives us the answer.
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