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Dear Shivam ,
the given word is PARAMETER.
and between every 2 consonants there is a vowel.
so given condition is that THERE IS NO VOWEL BETWEEN 2 CONSONANTS
so for that , we have to take all the vowels to ONE SIDE and FOR NOW treat them as a SINGLE letter.
vowels are : A , A , E , E
Consonants : P , R , M , T , R
let us take AAEE as one.
so total number = 5 + 1 = 6 (5 consonants + 1 vowel)
and number of words that can be made = 6! = 720
but the vowels can also be arranged in 4! / 2!*2! ways because 'A' appears twice and 'E' appears twice. = 6
so total number of words = 720 * 6 = 4320.
Please approve !
Dear student,
Keep all vowels together and all consonants together we have following ways:
4! * 4! /2! 2! 2!
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