Solve the inquality:

(3-x) / (15-x)^1/2 <1

The solution has to be of form (a,b)

(3-x) / (15-x)^1/2 <1

(3-x)  <(15-x)^1/2

(3-x)²  <|15-x|

case 1: x<15

(3-x)²  <15-x

therefore we get by solving this equation

x = (6,-1)

case 1: x>15

(3-x)²  <x-15

therefore we get,

x=(7+145^1/2)/2 , (7-145^1/2)/2

but both are less than 15,

thus no solution from this case

thus final answer is (6,-1)

I would like to point out that necessarily 15-x>0. So the case x>15 is redundant