If each pair of the following three equations: x2 + a1x + b1 = 0 , x2 + a2x + b2 = 0 and x2 + a3x + b3 = 0 has exactly one root in common, then show that ( a1 + a2 + a3 )2 = 4( a2a3 + a3a1 + a1a2 - b1 - b2 - b3).
If each pair of the following three equations: x2 + a1x + b1 = 0 , x2 + a2x + b2 = 0 and x2 + a3x + b3 = 0 has exactly one root in common, then show that ( a1 + a2 + a3 )2 = 4( a2a3 + a3a1 + a1a2 - b1 - b2 - b3).










