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if a,b,c are inG.P find the ratio of ax2+bx+c=0
this question is not clear , what ratio do you want us to find a:b:c in a GP the numbers are always in the ratio of r : 1 with the previous number so here the ratio is 1 : r : r2 where 'r' is the common term Find 'r' and then we get the ratio. Please approve !
this question is not clear , what ratio do you want us to find
a:b:c
in a GP the numbers are always in the ratio of r : 1 with the previous number
so here the ratio is
1 : r : r2 where 'r' is the common term
Find 'r' and then we get the ratio.
Please approve !
IF we are reqd to find the ratio between the roots of the equation ax2+bx+c=0.. then Let the roots be Y and Z.So reqd to find is Z/Y. Y+Z=-b/a YZ=c/a Let the common ratio of the gp be r Y+Z=-r and YZ=r2 or (Y+Z)2=YZ which gives Y2+Z2=-YZ Dividing by YZ we get Y/z +Z/Y=-1 If Y/Z =m then we have m+1/m=-1 which is impossible as sum of a No and its reciprocal iS alwyz >2 or <-2..so the equation wont have any real roots
IF we are reqd to find the ratio between the roots of the equation ax2+bx+c=0.. then
Let the roots be Y and Z.So reqd to find is Z/Y.
Y+Z=-b/a
YZ=c/a
Let the common ratio of the gp be r
Y+Z=-r and YZ=r2
or (Y+Z)2=YZ
which gives Y2+Z2=-YZ
Dividing by YZ we get Y/z +Z/Y=-1
If Y/Z =m then we have m+1/m=-1
which is impossible as sum of a No and its reciprocal iS alwyz >2 or <-2..so the equation wont have any real roots
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