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```
if a,b,c are inG.P find the ratio of ax2+bx+c=0

```
9 years ago

```							this question is not clear , what ratio do you want us to find
a:b:c
in a GP the numbers are always in the ratio of r : 1 with the previous number
so here the ratio is
1 : r : r2 where 'r' is the common term

Find 'r' and then we get the ratio.

```
9 years ago
```							IF we are reqd to find the ratio between the roots of the equation ax2+bx+c=0.. then
Let the roots be Y and Z.So reqd to find is Z/Y.
Y+Z=-b/a
YZ=c/a
Let the common ratio of the gp be r
Y+Z=-r and YZ=r2
or (Y+Z)2=YZ
which gives Y2+Z2=-YZ
Dividing by YZ we get Y/z +Z/Y=-1
If Y/Z =m then we have m+1/m=-1
which is impossible as sum of a No and its reciprocal iS alwyz >2 or <-2..so the equation wont have any real roots
```
9 years ago
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