Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
a.(1/33)*sigma(n=1 to n=16) {(4*n^4)/((4*n^2)-1)} = ? b.sigma(k=0 to k=n){(2^k)*(2nCk)} = ?
Dear student,
sigma(n=1 to n=16) {(4*n^4)/((4*n^2)-1)} =
4n^4/[(2n-1)(2n+1)] = 4n^4 -1+1/4n^2-1 = [4n^2 +1] + (1/2)[1/2n-1 - 1/2n+1]
sigma{[4n^2 +1]} = 4n(n+1)(2n+1)/6 + n put n= 16 ....... (1)
sigma{(1/2)[1/2n-1 - 1/2n+1]} = (1/2)[1+1/33] ....... (2)
add (1) and (2) gives solution
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -