x^2+18x-5|x+9|+87=0

Dear student,

In such questions take two cases

1)when mod term >0

2)when mod term <0

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

We can write the equation as 

Setting t= |x+9|, we get t=3 and t=2, both of which are admissible. So x=-12,-11,-7,-6 are the solutions.