Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x*2^n)=0=summation of sin(x*2^n) for all n____natural no.s

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Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x*2^n)=0=summation of sin(x*2^n) for all n____>natural no.s

SAGAR SINGH - IIT DELHI · Answer

Dear student,

In this case apply the Arithmetic sum of sine series as well as cosine series which you have learnt in complex numbers or go thru ML Khanna

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Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x2^n)=0=summation of sin(x2^n) for all n____>natural no.s

Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x2^n)=0=summation of sin(x2^n) for all n____>natural no.s

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Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x*2^n)=0=summation of sin(x*2^n) for all n____>natural no.s

Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x*2^n)=0=summation of sin(x*2^n) for all n____>natural no.s

1 Answers

Think You Can Provide A Better Answer ?

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Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x2^n)=0=summation of sin(x2^n) for all n____>natural no.s

Question: x,y ,z are real numbers such that summation of cos x=0=summation of sinx. Prove that summation of (x2^n)=0=summation of sin(x2^n) for all n____>natural no.s