badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 12 

                        
sinx=logx how many solutions have for this? (when x in degree and x in radian)
9 years ago

Answers : (2)

vikas askiitian expert
509 Points 
							
draw two curves ,


f(x) = sinx &  f(x) = logx


these two curves intersect at 1 point .....


total solutions of sinx = logx are 1 ...
9 years ago
Durgesh Prasher
21 Points 
							
infinitely many solutons are possible
9 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Algebra

Find the set of values of k for which the equation x^4 + kx^2 + k=0 has purely imaginary roots. Answer & Earn Cool Goodies
if a,b and c are three different complex numbers such that a/1-a=b/1-b=c/1-c=k then k=? Answer & Earn Cool Goodies
Given : 1/16 ÷ 1/81 + - 1/8 To find: multiplicative inverse
In ∆ PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and...
Write the contrapositive of the given if-then statements: (a) If a triangle is equilateral, then it...
View all Questions »


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details