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lower limitk=1 upper limit 10 (sin2kpi/11+icos2kpi/11)

MANOJ KUMAR , 14 Years ago
Grade 12
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vikas askiitian expert

Last Activity: 14 Years ago

Z = sin2kpi/11 + icos2kpi/11

Z = Aei@                    (ellulers form)

A = (sin2@+cos2@)1/2 = 1 ,

@ = 2kpi/11

Z = ei(2kpi/11) 

sigma Z  = sigma ei(2kpi/11)   lim k=1 to k=10

            =ei[2pi/11 (1+2+3........10)]  (AP series)                         [ sum of Ap is n/2(2a+(n-1)d]

           =ei[2pi/11(55)]

           =ei10pi = cos10pi + isin10pi = 1

mycroft holmes

Last Activity: 14 Years ago

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