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```
lower limit k=1 upper limit 10 (sin2kpi/11+icos2kpi/11)

```
10 years ago

509 Points
```							Z = sin2kpi/11 + icos2kpi/11
Z = Aei@                    (ellulers form)
A = (sin2@+cos2@)1/2 = 1 ,
@ = 2kpi/11
Z = ei(2kpi/11)
sigma Z  = sigma ei(2kpi/11)   lim k=1 to k=10
=ei[2pi/11 (1+2+3........10)]  (AP series)                         [ sum of Ap is n/2(2a+(n-1)d]
=ei[2pi/11(55)]
=ei10pi = cos10pi + isin10pi = 1
```
10 years ago
mycroft holmes
272 Points
```
```
10 years ago
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• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions