badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

lower limit k=1 upper limit 10 (sin2kpi/11+icos2kpi/11)

9 years ago

Answers : (2)

vikas askiitian expert
509 Points
							

Z = sin2kpi/11 + icos2kpi/11

Z = Aei@                    (ellulers form)

A = (sin2@+cos2@)1/2 = 1 ,

@ = 2kpi/11

Z = ei(2kpi/11) 

sigma Z  = sigma ei(2kpi/11)   lim k=1 to k=10

            =ei[2pi/11 (1+2+3........10)]  (AP series)                         [ sum of Ap is n/2(2a+(n-1)d]

           =ei[2pi/11(55)]

           =ei10pi = cos10pi + isin10pi = 1

9 years ago
mycroft holmes
272 Points
							

9 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details