prove that [1-2n +2n(n-1)/2!] - [2n(2n-1)(2n-2)/3!]...+[(-1)n-12n(2n-1)...(n+2)/(n-1)!] = (-1)n+1(2n)!/1(n!)2
prove that [1-2n +2n(n-1)/2!] - [2n(2n-1)(2n-2)/3!]...+[(-1)n-12n(2n-1)...(n+2)/(n-1)!] = (-1)n+1(2n)!/1(n!)2
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