the solution of a problem is this:
Total number of words = 5! = 120!
If all the vowels come together, then we have: (O.E.A.), M,G
These can be arranged in 3! ways.
But (O,E.A.) can be arranged themselves in 3! ways.
=> Number of ways, when vowels come-together = 3! x 3!
= 36 ways
=> Number of ways, when vowels being never-together
= 120-36 = 84 ways.
but why not,
like this:-
O X E X A
over here the position of X can be filled by 2! ways and OEA in 3! ways,what more selections am i missing?
becoz total ways according to my analysis is 12 but according to this process is 84.
the solution of a problem is this:
Total number of words = 5! = 120!
If all the vowels come together, then we have: (O.E.A.), M,G
These can be arranged in 3! ways.
But (O,E.A.) can be arranged themselves in 3! ways.
=> Number of ways, when vowels come-together = 3! x 3!
= 36 ways
=> Number of ways, when vowels being never-together
= 120-36 = 84 ways.
but why not,
like this:-
O X E X A
over here the position of X can be filled by 2! ways and OEA in 3! ways,what more selections am i missing?
becoz total ways according to my analysis is 12 but according to this process is 84.
Anmol Nanda , 15 Years ago
Grade 11
