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The answer of sum upto n terms is,
(2n+1)(n+1)+ 3n(n+1) + 3n
Let
Sn= 1+5+13+25+........T(n-1)+Tn
Sn= 1+5+13+25.................T(n-1)+Tn
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now subtracting the two equations
0=1+4+8+12+.......upto n terms -Tn
Tn=1+(4+8+12+.......upto (n-1)terms)
Tn=1+((n-1)/2[8+(n-2)4]
solve it to get the nth term
and to solve it use summation method
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