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Q. How many 6-digit numbers are there, in which the sum of the digits is even?
Dear Raghu, Total no of 6 digit numbers possible = 9x10x10x10x10x10=9 x 105 ( excludign those starting with 0 and when the repetition of digits is allowed) now 1st no is 100000....teh sum of the digits for this no is 1 which is odd next no is 100001....the sum of the digits is 2 which is even ........ this series will go on till 999999 so the required no of 6 digited numbers will be 1/2 of 9 x 105 = 4.5 x 105 = 45 x 104 numbers.. Ashray Jain HOMI BATCH
Dear Raghu,
Total no of 6 digit numbers possible = 9x10x10x10x10x10=9 x 105 ( excludign those starting with 0 and when the repetition of digits is allowed)
now 1st no is 100000....teh sum of the digits for this no is 1 which is odd
next no is 100001....the sum of the digits is 2 which is even
........
this series will go on till 999999
so the required no of 6 digited numbers will be 1/2 of 9 x 105 = 4.5 x 105 = 45 x 104 numbers..
Ashray Jain
HOMI BATCH
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