Anil Pannikar AskiitiansExpert-IITB
Last Activity: 14 Years ago
Dear Aparna,
let common root is X and as other roots are in the ratio 3:4 so, let one root is x2 and other is x1 = 3x2/4
(x^2)-6x+a=0 : Sum of roots = 6 = X + x2 ....1 and product = a = X*x2
(x^2)-cx+6=0 : Sum = c = X + 3x2/4 .....2 and product = 6 = X*x2/4
from 1 and 2 : 6-x2=c-3x2/4, so x2 = 24-4c, X = 24/24-4c and a = 24
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Anil Pannikar
IIT Bombay