Pratham Ashish
Last Activity: 15 Years ago
hi vaibhav,
d given exp is a gp wid r = (x+1)/(x+2)
just write d sum of d given gp , u will get
here , a = (x+2)^n
and sum = a(1-r^n)/(1-r)
after simplifying u will get (x+2)( (x+2)^n - (x+1)^n ) )
nw take 2 from (x+2)^n and write in simple form as 2^n (1+ x/2)^n and u know dat coeff of x^r is nCr ,so use dis n u will get d final result as
(2^(n-r+1) - 1)*((n+1)Cr ) - nCr so ans wud be (d)none of these.