1.SIMPLIFY

log2 + 16log16/15 + 12 log + 7log81/80

2. IF 2logx^2y = 3 + logx - logy and

x - y = 3 ......find x and y (given that x and y are +ve real numbers)

3.If n = 2003! evaluate 1/log(base 2)n + 1/log(bse 3)n+.....+1/log(base2003)n

4. IF logx/b-c = logy/c-a= logz/a-b then find the value of x^b+c-a.y^c+a-b

+ za+b-c

THANK U........PLZ DO EXPLAIN PROCEDURE

Pooja singh

15 Years agoGrade 11