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1.SIMPLIFY log2 + 16log16/15 + 12 log + 7log81/80 2. IF 2logx^2y = 3 + logx - logy and x - y = 3 ......find x and y (given that x and y are +ve real numbers) 3.If n = 2003! evaluate 1/log(base 2)n + 1/log(bse 3)n+.....+1/log(base2003)n 4. IF logx/b-c = logy/c-a= logz/a-b then find the value of x^b+c-a.y^c+a-b + za+b-c THANK U........PLZ DO EXPLAIN PROCEDURE

1.SIMPLIFY


log2 + 16log16/15 + 12 log + 7log81/80


2. IF 2logx^2y = 3 + logx - logy and


x - y = 3 ......find x and y (given that x and y are +ve real numbers)


3.If n = 2003! evaluate 1/log(base 2)n + 1/log(bse 3)n+.....+1/log(base2003)n


4. IF logx/b-c = logy/c-a= logz/a-b then find the value of x^b+c-a.y^c+a-b


+ za+b-c


THANK U........PLZ DO EXPLAIN PROCEDURE

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

Please ask only one question per post

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