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We know that,13=12+21d⇒d=−16×21 ⋯(1)Now, given H1+2H1−2+H20+3H20−3=12+1H112−1H1+13+1H2013−1H20=12+12+d12−d−12+13+13−d13−13+d(∵1H1=12+d, 1H20=13−d)=1+d−d+23−dd=23−d−1−dd=−13−2dd=−13d−2=6×213−2=40 [Using equation (1)]
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