Join now for JEE/NEET and also prepare for Boards Class 10 Boards Cancelled! What to do next ? Ask our Experts in a Free Counseling Session Now ! Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
find the number of ways 1 can put 3 balls numbered 1,2,3 in three boxes labelled a,b,c such that at the most one box is empty
We have three diff balls and three diff box .
Now at most one box is empty - so there are two cases
1. None box is empty
2. One box is empty
therefore , if none box is empty number of ways =3x2x1 =6
if one box is empty , we can choose that box in 3 ways and the 3 balls can be put in two boxes in 3P2 ways .
so number of ways in case 2= 3x3p2= 3x6=18
therefore total number of ways = 18+6=24
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !