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Among the 8! permutations of the digits 1,2,3,.....8, consider those arrangements which have the following property:if you take any 5 consecutive positions , the product of the digits in those positions is divisible by 5.find the number of such arrangements?

Rahul Ramesh , 14 Years ago
Grade 11
anser 1 Answers
mycroft holmes

Last Activity: 14 Years ago

Its obvious that the number 5 has to be in the 4th position or 5th position. The number of possible arrangements is therefore 7! X 2.

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