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i m not gettin right ans.... (2.4)^x=(2.6)^x-1 has1. no solution 2. exactly one solution 3. at least two solution 4. infinite number of solution
i m not gettin right ans....
(2.4)^x=(2.6)^x-1
has1. no solution
2. exactly one solution
3. at least two solution
4. infinite number of solution
Hii vibhor
(2.4)^x = (2.6)^(x-1)
(2.4)^x = (2.6)^x / (2.6)
(2.4/2.6)^x = 1/(2.6)
(12/13)^x = 5/13
So this gives a conclusion that it has one solution lying between (0,1)
Regards
Yagya
askiitians_expert
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