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chua kok tong Grade: Upto college level
        You are given a sequence 1,1,2,3,5,8,13,21,... , what is the remainder of 2500 term when divided by8
7 years ago

Answers : (1)

Anil Pannikar AskiitiansExpert-IITB
85 Points

Dear  Chua kok tong,


1,   1,   2,        3,        5,        8,          13,         21,...  34  55

          1+1,   1+2,    2+3,   3+5,       8+5,        ......

Let n be the 2500 term, so,   (n-1)th term + ( n-2)th term = nth term

                                 and     (n+2)th term - (n+1 )th term = nth term

0, 1,   1,   2,        3,        5,        8,          13,         21.......

this is called as Fibonacci series, the direct formula is..

F(n)=[ {(1+√5)/2}n-{(1-√5)/2}n ]/√5

given sequence starts from 1 so we will find 2501 th term, so n = 2501

find value and divide by 8.



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Askiitians Expert

Anil Pannikar

IIT Bombay

7 years ago
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