###### Anil Pannikar AskiitiansExpert-IITB

Last Activity: 14 Years ago

Dear ** **Chua kok tong,

**1, 1, 2, 3, 5, 8, 13, 21,... 34 55**

** 1+1, 1+2, 2+3, 3+5, 8+5, ......**

Let n be the 2500 term, so, (n-1)th term + ( n-2)th term = nth term

and (n+2)th term - (n+1 )th term = nth term

**0, 1, 1, 2, 3, 5, 8, 13, 21.......**

**this is called as Fibonacci series, the direct formula is..**

F(n)=[ {(1+√5)/2}^{n}-{(1-√5)/2}^{n} ]/√5

given sequence starts from 1 so we will find 2501 th term, so n = 2501

find value and divide by 8.

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Askiitians Expert

Anil Pannikar

IIT Bombay