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Dear Chua kok tong,
1, 1, 2, 3, 5, 8, 13, 21,... 34 55
1+1, 1+2, 2+3, 3+5, 8+5, ......
Let n be the 2500 term, so, (n-1)th term + ( n-2)th term = nth term
and (n+2)th term - (n+1 )th term = nth term
0, 1, 1, 2, 3, 5, 8, 13, 21.......
this is called as Fibonacci series, the direct formula is..
F(n)=[ {(1+√5)/2}n-{(1-√5)/2}n ]/√5
given sequence starts from 1 so we will find 2501 th term, so n = 2501
find value and divide by 8.
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