0

Guest

Courses New

if the root of the equation x 2 -ax+b=0 differ by unity a 2 is equal to 1+a 2 is equal to if one of the root of the equation x 2 -ax+b=0 be twice the other then 2a 2 is equal to if the sum of the root of the equation x 2 -ax+b=0 is equal to the sum of the square of their reciprocal then a 2 is equal to

if the root of the equation x2-ax+b=0 differ by unity



  1. a2 is equal to

  2. 1+a2 is equal to

  3. if one of the root of the equation x2-ax+b=0 be twice the other then 2a2 is equal to

  4. if the sum of the root of the equation x2-ax+b=0 is equal to the sum of the square of their reciprocal then a2 is equal to

Grade:12

1 Answers

SAGAR SINGH - IIT DELHI
879 Points
12 years ago

Dear jiya,

Let p ad p+1 be the roots

p+p+1=a

P(P+1)=b

p=a-1/2

(a-1)/2(a-1/2+1)=b

a^2-1=4b

a^2=4b+1

a^2+1=4b+2

 

We are all IITians and here to help you in your IIT JEE preparation.

All the best.

 If you like this answer please approve it....

win exciting gifts by answering the questions on Discussion Forum

 

Sagar Singh

B.Tech IIT Delhi

sagarsingh24.iitd@gmail.com

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More