if the root of the equation x 2 -ax+b=0 differ by unity a 2 is equal to 1+a 2 is equal to if one of the root of the equation x 2 -ax+b=0 be twice the other then 2a 2 is equal to if the sum of the root of the equation x 2 -ax+b=0 is equal to the sum of the square of their reciprocal then a 2 is equal to

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SAGAR SINGH - IIT DELHI · Answer

Dear jiya,

Let p ad p+1 be the roots

p+p+1=a

P(P+1)=b

p=a-1/2

(a-1)/2(a-1/2+1)=b

a^2-1=4b

a^2=4b+1

a^2+1=4b+2

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