Chetan Mandayam Nayakar
Last Activity: 14 Years ago
sin2(theta) + cos2(theta) = (sinθ +cosθ)2 -2sin(theta)cos(theta) =1
sin(theta) +cos(theta) = -b/a, sin(theta)cos(theta) =c/a
therefore b2/a2 -2c/a =1, a2-b2 +2ac=0
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