4. if sin θ and cos θ are the roots of the equations ax2-bx2+c = 0, then a, b and c satisfy the relation.

(a) a²+b²+2ac=0

(b) a²-b²+2ac=0

(c) a²+c²+2ac=0

(d) a²-b²-2ac=0

sin²(theta) + cos²(theta) = (sinθ +cosθ)² -2sin(theta)cos(theta) =1

sin(theta) +cos(theta) = -b/a, sin(theta)cos(theta) =c/a

therefore b²/a² -2c/a =1, a²-b² +2ac=0 

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