Flag Algebra> find value of (x+y)^2...
question mark

if x^2 + y^2 = 4 (x+y-2),then value of (x+y)^2 is

(A) 4 (B) 0 (C) 16 (D) 20

Shobhit Gupta , 16 Years ago
Grade 12
anser 1 Answers
piyush garg

x^2+y^2=4x+4y-8 this represents apoint circle whose radius is zero and centre is (2,2)

(x-2)^2 +(y-2)^2=0 hence it represents apoint x=2 and y=2 therefore (x+y)^2 is (2+2)^2 =16 ans

Last Activity: 16 Years ago
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