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Plz solve this Question!!! The sum of the three numbers in A.P is 21 and the product of their extremes is 45. Find the numbers.
Plz solve this Question!!!
The sum of the three numbers in A.P is 21 and the product of their extremes is 45. Find the numbers.
Let the numbers are be a - d, a, a + d Then a - d + a + a + d = 21 3a = 21 a = 7 and (a - d)(a + d) = 45 a2 - d2 = 45 d2 = 4 d = +2 Hence, the numbers are 5, 7 and 9 when d = 2 and 9, 7 and 5 when d = -2. In both the cases numbers are the same.
Let the numbers are be a - d, a, a + d
Then a - d + a + a + d = 21
3a = 21
a = 7
and (a - d)(a + d) = 45
a2 - d2 = 45
d2 = 4
d = +2
Hence, the numbers are 5, 7 and 9 when d = 2 and 9, 7 and 5 when d = -2. In both the cases numbers are the same.
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