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Plz solve this Question!!! The sum of the three numbers in A.P is 21 and the product of their extremes is 45. Find the numbers.
Let the numbers are be a - d, a, a + d Then a - d + a + a + d = 21 3a = 21 a = 7 and (a - d)(a + d) = 45 a2 - d2 = 45 d2 = 4 d = +2 Hence, the numbers are 5, 7 and 9 when d = 2 and 9, 7 and 5 when d = -2. In both the cases numbers are the same.
Let the numbers are be a - d, a, a + d
Then a - d + a + a + d = 21
3a = 21
a = 7
and (a - d)(a + d) = 45
a2 - d2 = 45
d2 = 4
d = +2
Hence, the numbers are 5, 7 and 9 when d = 2 and 9, 7 and 5 when d = -2. In both the cases numbers are the same.
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