if x=cy+bz,y=az+cx,and z=bx+ay,show that

x²/1-a²=y²/1-b²=z²/1-c²

Hello student,
Please find the answer to your question below
x = cy + bz y = az + cx
y = az + c^2y + cb
(1 - c^2)y = (a+bc)z
meanwhile z = bx + ay z = bcy + b^2z + ay (1 - b^2)z = (a + bc)y
from first set: y/(a+bc) = z/(1 - c^2)
(a + bc)y/(1 - b^2) = z
multiply left equation to left.. and right equation to right equation also .
y^2/(1 - b^2) = z^2/(1 - c^2) then you can continue with the rest of the equation