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x+y^(1/2)=7

x^(1/2)+y=11

Pratyush agarwal , 15 Years ago

Grade

1 Answers

Jitender Singh

Ans:
Hello Student,
Please find answer to your question below

$x + \sqrt{y} = 7$
$\sqrt{x} + y = 11$
$y = (7-x)^{2}$
$\sqrt{x} = 11 - y$
$x = 121 + y^{2} - 22y$
$x = 121 + (7-x)^{4} - 22(7-x)^{2}$
$x = 121 + (x^{2}-14x+49)^{2} - 22(x^{2}-14x+49)$
$x = 121 + (x^{4}+196x^{2}+49^{2}-28x^{3}+98x^{2}-1372x) - 22(x^{2}-14x+49)$
$x^{4} -28x^3 + 272x^{2}-1065x + 49^{2}-957 = 0$

$x^{4} -28x^3 + 272x^{2}-1065x + 1444 = 0$
$\Rightarrow x = 4, 3.415, 9.805, 10.78$

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