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how to find the othrocenter of a trianle whoose vertices are A(0,0) b(-1,3) c (2,-1)
Dear gaurav
Orthocenter is the point of intersection of altitude
so find the equation of line which is perpendicular to the line joing point (-1,3) and (2,-1) and passes through (0,0)
slope of the line BC = -1/2
slope of the line perpendicular to it =2
so equation of line : y-3 =2 (x+1)
or 2x-y +5=0
now find another line which is perpendicular to the line joing point (0,0) and (2,-1) and passes through (-1,-3)
slope of the line AC = -4/3
slope of the line perpendicular to it =3/4
so equation of line : y =3/4 x
or 3x-4y =0
solve these two equation
x=-4 , y =-3
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