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let z = cosa + i sina, then summation of z 2m-1 from m=1 to 15 at a=2 is what ???? Please give detailed, explained answer. thank you....
z=e^ia in euler form Z^(2m-1)=e^(2m-1)i summmission of cos(2m-1)a+isin(2m-1)a from m to 1 to 15 cos(1+2....................................29)a+isin (1+2...............................29)a cos(225a) +isin(225a) put a=2 cos(450)+isin(450) =i ans.
z=e^ia in euler form
Z^(2m-1)=e^(2m-1)i
summmission of cos(2m-1)a+isin(2m-1)a from m to 1 to 15
cos(1+2....................................29)a+isin (1+2...............................29)a
cos(225a) +isin(225a)
put a=2
cos(450)+isin(450)
=i ans.
Z=COSA+i sinA =e^iA (euclid's eq.) SUMMATION OF Z^2m-1 = e^(iA)(2*1-1) + it wil form G.P ANS ----------(e^2i)(e^60i -1)/(e^4i -1)
Z=COSA+i sinA
=e^iA (euclid's eq.)
SUMMATION OF Z^2m-1 = e^(iA)(2*1-1) + it wil form G.P
ANS ----------(e^2i)(e^60i -1)/(e^4i -1)
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