if a-b=3 and a3 -b3=117 ,then what is the value of a+b
a-b=3
Cubing both sides, we get:
a3-b3-3ab(a-b)=27
117-3ab(3)=27
-9ab=-90
ab=10
a3-b3=(a-b)(a2+b2+ab)
117=3[(a+b)2+ab]
39=(a+b)2+10
(a+b)2=40
a+b=±7
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Last Activity: 2 Years ago
Last Activity: 3 Years ago