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question mark

The value of 4 {nC1 + 4 . nC2 + 42 . nC3 + ...... + 4n - 1} is :
0
5n + 1
5n
5n - 1

VISHWESH RAVI , 15 Years ago
Grade 12th Pass
anser 1 Answers
Nehal Wani

Last Activity: 15 Years ago

(1+x)n=nC0x0+ nC1x1+ nC2x2+ nC3x3+………………….+ nCnxn-1+ nCnxn

Put x=4

5n= nC040+ nC141+ nC242+ nC343+………………….+ nCn4n-1+ nCn4n

5n=nC040+4{ nC1+ nC24+ nC342+………………….+ nCn4n-2+ 4n-1}

4{ nC1+ nC24+ nC342+………………….+ nCn4n-2+ 4n-1}=5n-1

 

 

 

 

 

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