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SHOW THAT THE RATIO OF SUM OF FIRST n terms of gp to sum of terms from [n+1]th to [2n]th term is 1/r raise to power n

SHOW THAT THE RATIO OF SUM OF FIRST n terms of gp to sum of terms from [n+1]th to [2n]th term is 1/r raise to power n

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2 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
10 years ago
Hello student,
Please find the answer to your question below
Given The numbers are in GP
Then sum of first n terms of a GP is a(rn-1)/r-1
Sum of terms from n+1 to 2n terms of a GP is a(r2n-1)/r-1
So The ratio of them gives (rn-1)/(r2n-1)=(1/rn+1)
But the 1 in denominator can be neglected because rnis>>>1
SoTHE RATIO OF SUM OF FIRST n terms of gp to sum of terms from [n+1]th to [2n]th term is (1/rn)
kasilaxmi
37 Points
10 years ago
hi farru

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