SHOW THAT THE RATIO OF SUM OF FIRST n terms of gpto sum of terms from [n+1]th to [2n]th termis 1/r raise to power n

Hello student,
Please find the answer to your question below
Given The numbers are in GP
Then sum of first n terms of a GP is a(rⁿ-1)/r-1
Sum of terms from n+1 to 2n terms of a GP is a(r²ⁿ-1)/r-1
So The ratio of them gives (rⁿ-1)/(r²ⁿ-1)=(1/rⁿ+1)
But the 1 in denominator can be neglected because rⁿis>>>1
SoTHE RATIO OF SUM OF FIRST n terms of gp to sum of terms from [n+1]th to [2n]th term is (1/rⁿ)