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A circle passes through the points (-1,3)and (5,11) and its radius is 5. Then its centre is?
Dear tadi parthi Let the center is (h,k) so (h+1)2 + (k-3)2 = (h-5)2 +(k-11)2 =52 so (h+1)2 + (k-3)2 = (h-5)2 +(k-11)2 simplify 3h +4k=34 ...............1 and (h+1)2 + (k-3)2 =52 h2 +k2 +2h -6k =15 ..............2 solve 1st and 2nd equation that will desired solution Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get youthe answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
Dear tadi parthi
Let the center is (h,k)
so (h+1)2 + (k-3)2 = (h-5)2 +(k-11)2 =52
so (h+1)2 + (k-3)2 = (h-5)2 +(k-11)2
simplify
3h +4k=34 ...............1
and (h+1)2 + (k-3)2 =52
h2 +k2 +2h -6k =15 ..............2
solve 1st and 2nd equation
that will desired solution
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get youthe answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
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