Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Dear Padmavithi
Only 2 tests will be needed to find the faulty machines if we can find one faulty machine in each test
Probality that we will test a faulty machine in first test is 2/4=1/2 (there are 4 machines and 2 of them faulty)
Now that one faulty machine has been identified we are left with 3 machines with one of them being faulty.Probaility that we will test the other faulty machine in second test is 1/3.so probability that we will require 2 tests to find the faulty machines is 1/2*1/3=1/6
ALL THE BEst
ABhinav Batra
Hi,
there are 2 ways of getting the machines in the first 2 tries. First possibility, you get both faulty, or you get both correct(since, then you know the left ones are faulty). Thus solving both possibilities: (2/4)x (1/3) x 2 since both have same chances. Hence solving Answer is: 1/3
Thanks
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !