Hello student, Please find the answer to your question below given a+b=c+d and a3+b3=c3+d3 So (a+b)(a2-ab+b2)=(c+d)(c2-cd+d2) As a+b=c+d ;(a2-ab+b2)=(c2-cd+d2) So (a+b)2-3ab=(c+d)2-3cd So ab=cd also (a+b)2-4ab=(c+d)2-4cd So (a-b)2=(c-d)2 SO a+b=c+d and a-b=c-d So a=c,b=d Soa2011+b2011=c2011+d2011
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